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![Q. Guiven, Ka = 5.2818-5 de la prika = 112x10-4 - Using integrated tom at T = 443 k. at T2 = 453K se 1: 24 453-4UR 52xic ] 2.](http://img.homeworklib.com/questions/70d2ad10-afb1-11ea-b773-49ded415a6c9.png?x-oss-process=image/resize,w_560)
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The table of data below gives experimental data fork for a catalyzed synthesis at three different...
3. The rate constant has been determined at several different temperatures. When the data is graphed...
3. The rate constant has been determined at several different temperatures. When the data is graphed as in k vs. 1/T (K-!), the slope of the line is -1.48 x 104 and the y-intercept is 24.6. What is the activation energy, E, for this reaction? a. 9.62 kJ b. 15.0 kJ c. 123 kJ d. 205 kJ e. 1214 kJ I 4. For the reaction (CH3), CBr(aq) + OH" (aq) → (CH), COH(aq) +Br"(aq) the following data were obtained at...
The rate constant for the synthesis reaction in the presence of a Fe-based catalysts has been...
The rate constant for the synthesis reaction in the presence of a Fe-based catalysts has been determined at various temperatures. The table presents the results: T(C) k (s") 25 100 200 300 400 3.24 x 10° 2.32 x 10° 5.81 x 104 2.11 x 102.64 x 10 11. Use the data provided to determine the activation energy in the presence of the Fe-based catalyst (graphing method, you will need a spreadsheet program: e.g., Excel, google sheets). 12. Estimate how many...
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation...
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation energy of the reaction in kJ/mol. Note: R = 8.314 J/(mol*K) = 0.008314 kJ/(mol*K) = 0.0821 L*atm/(mol*K) Arrhenius Plot: Sample Data o e đ d c In(k) đ ở s y = -18808x + 56.183 R2 = 0.976 do o o 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 1/T
Need answer and explanation please! one-half c. first e. three-halves the following data, determine the e...
Need answer and explanation please!
one-half c. first e. three-halves the following data, determine the e the order of the reaction with respect to ICL Experiment [Hal (torr) ICij ( 250 250 50 (torr) Rate (Mis) 325 81 325 1.34 0.331 0.266 a one-half b. first c. second d. third e. three-halves 21. pops was measured at two different temperatures. How many times pop at 250°C compared with that at 210 C when the activation energy is The rate at...
a Review | Constants Periodic Table Part A The Arrhenius equation shows the relationship between the...
a Review | Constants Periodic Table Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k= Ae-E/RT where R is the gas constant (8.314 J/mol K). A is a constant called the frequency factor, and E is the activation energy for the reaction. The activation energy of a certain reaction is 47.9 kJ/mol. At 25 °C, the rate constant is 0.0190s . At what temperature...
The rate data of the reaction was collected at different temperatures (°C) and functions of the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
please help me find part 2 in this question with explanation. thanks Print Periodic Table Ebook...
please help me find part 2 in this question with explanation.
thanks
Print Periodic Table Ebook Question 11 of 18 (1 point) X Incorrect X In The rate constant for the reaction of nitrogen with oxygen was determined at four temperatures. Calculate the activation energy and frequency factor A for the reaction given the data below. N, (g) o g) 2 NO (g) T (K) k (cm /molecule s) Number 250 7.18 x 10-8 14.2 kJ mol 275 1.36 x...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?]...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
please answer 11 and 12 25 The rate constant for the synthesis reaction T("C) 100 200...
please answer 11 and 12
25 The rate constant for the synthesis reaction T("C) 100 200 300 400 in the presence of a Fe-based catalysts has been determined at various temperatures. k (s") 3.24 x 10° 2.32 x 109 5.81 x 10+ 2.11 x 10- 2.64 x 10 The table presents the results: 11. Use the data provided to determine the activation energy in the presence of the Fe-based catalyst (graphing method, you will need a spreadsheet program: e.g., Excel,...
Ent //n Data and Calculations: Enter your experimental data and calculations in the data sheet below....
Ent //n Data and Calculations: Enter your experimental data and calculations in the data sheet below. g/mol Qmmonium g/mol B6.043 LLo. 95 Determination of the Heat of Solution Molecular weight of: NH.NO, (Salt A) CaCl (Salt B) 27 0 s): With NH4NO, With CaCl C Temperature of water before mixing (t (a) Temperature of solution after mixing: 10 100 110 90 120 80 70 60 5C 3C 40 20 Time (s) Salt A 841 35 8s 35 33 32 32...
3. The rate constant has been determined at several different temperatures. When the data is graphed as in k vs. 1/T (K-!), the slope of the line is -1.48 x 104 and the y-intercept is 24.6. What is the activation energy, E, for this reaction? a. 9.62 kJ b. 15.0 kJ c. 123 kJ d. 205 kJ e. 1214 kJ I 4. For the reaction (CH3), CBr(aq) + OH" (aq) → (CH), COH(aq) +Br"(aq) the following data were obtained at...
The rate constant for the synthesis reaction in the presence of a Fe-based catalysts has been determined at various temperatures. The table presents the results: T(C) k (s") 25 100 200 300 400 3.24 x 10° 2.32 x 10° 5.81 x 104 2.11 x 102.64 x 10 11. Use the data provided to determine the activation energy in the presence of the Fe-based catalyst (graphing method, you will need a spreadsheet program: e.g., Excel, google sheets). 12. Estimate how many...
Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation energy of the reaction in kJ/mol. Note: R = 8.314 J/(mol*K) = 0.008314 kJ/(mol*K) = 0.0821 L*atm/(mol*K) Arrhenius Plot: Sample Data o e đ d c In(k) đ ở s y = -18808x + 56.183 R2 = 0.976 do o o 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 1/T
Need answer and explanation please!
one-half c. first e. three-halves the following data, determine the e the order of the reaction with respect to ICL Experiment [Hal (torr) ICij ( 250 250 50 (torr) Rate (Mis) 325 81 325 1.34 0.331 0.266 a one-half b. first c. second d. third e. three-halves 21. pops was measured at two different temperatures. How many times pop at 250°C compared with that at 210 C when the activation energy is The rate at...
a Review | Constants Periodic Table Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k= Ae-E/RT where R is the gas constant (8.314 J/mol K). A is a constant called the frequency factor, and E is the activation energy for the reaction. The activation energy of a certain reaction is 47.9 kJ/mol. At 25 °C, the rate constant is 0.0190s . At what temperature...
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
please help me find part 2 in this question with explanation.
thanks
Print Periodic Table Ebook Question 11 of 18 (1 point) X Incorrect X In The rate constant for the reaction of nitrogen with oxygen was determined at four temperatures. Calculate the activation energy and frequency factor A for the reaction given the data below. N, (g) o g) 2 NO (g) T (K) k (cm /molecule s) Number 250 7.18 x 10-8 14.2 kJ mol 275 1.36 x...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
please answer 11 and 12
25 The rate constant for the synthesis reaction T("C) 100 200 300 400 in the presence of a Fe-based catalysts has been determined at various temperatures. k (s") 3.24 x 10° 2.32 x 109 5.81 x 10+ 2.11 x 10- 2.64 x 10 The table presents the results: 11. Use the data provided to determine the activation energy in the presence of the Fe-based catalyst (graphing method, you will need a spreadsheet program: e.g., Excel,...
Ent //n Data and Calculations: Enter your experimental data and calculations in the data sheet below. g/mol Qmmonium g/mol B6.043 LLo. 95 Determination of the Heat of Solution Molecular weight of: NH.NO, (Salt A) CaCl (Salt B) 27 0 s): With NH4NO, With CaCl C Temperature of water before mixing (t (a) Temperature of solution after mixing: 10 100 110 90 120 80 70 60 5C 3C 40 20 Time (s) Salt A 841 35 8s 35 33 32 32...
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