Question

a Review | Constants Periodic Table Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k= Ae-E/RT where R is the gas constant (8.314 J/mol K). A is a constant called the frequency factor, and E is the activation energy for the reaction. The activation energy of a certain reaction is 47.9 kJ/mol. At 25 °C, the rate constant is 0.0190s . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. However, a more practical form of this equation is View Available Hint(s) ne ( ) which is mathmatically equivalent to ? 1: A Ty= Value A O Units In the where ki and k2 are the rate constants for a single reaction at two different absolute temperatures (7) and T2). Submit Part B Given that the initial rate constant is 0.0190s at an initial temperature of 25 °C. what would the rate constant be at a temperature of 140. " for the same reaction described in Part A? Express your answer with the appropriate units. View Available Hint(s) k2 = Value Units Submit

Answer 1

A) KEY] m2 = won ] 2 0.12 = 1000 looo - 1000 1000 3.3 7 T2 = 1000 = 308.64K 3:24 = 35.60c (%) en kan O 09 522 0.019 2 149.- 0.019 ) 4.12 ST