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Question 4 2 pts You generate the below Arrhenius plot of your data. Determine the activation...
Question 24 (1 point) The graph below shows the results of an Arrhenius plot for the...
Question 24 (1 point) The graph below shows the results of an Arrhenius plot for the reaction 2 N2O(g) --> 4 NO2(g) + O2(g) In(k) vs. 1/1 In(k) (k in units of s.1) slope-1.24x104 K intercept=315 -14 0.0026 0.0028 0.003 0.0032 0.0034 Т (1/к) Which of the following most correctly describes the activation energy and frequency factor for this reaction? Ea-1.03x102 kJ mol 1 A-3.30x1031 - 1 Ea=-1.24x104 kJ mol-1, A=31.5 s -1 O Ea-1.03x108 kJ mol-1 A-4.79x1013 5-1 Ea=1.03x102...
Examine the graph below and determine the value of the energy of activation for the chemical...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 y=-11624x + 32.055 R2 = 1 2 In k -3 -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) -96654 J/mol +96654 J/mol - 11624 J/mol +11624 J/mol -32.055 J/mol +32.055 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y = -11624x + 32.055 R2 = 1 -2 In k 3 -4 -5 -6 0.0028 0.0029 0.003 0.0031 0.0032 0.0033 1/T (1/K) -32.055 J/mol +32.055 J/mol -96654 J/mol +11624 J/mol - 11624 J/mol +96654 J/mol
Help with the work please!! Question 3 0/3 pts An Arrhenius plot has a slope of...
Help with the work please!!
Question 3 0/3 pts An Arrhenius plot has a slope of -13,796 K and an intercept of 6.72. What is the activation energy in kJ/mol? Report your answer to three significant figures. 20 50 er 115 margin of error +/- 2%
QUESTION 3 Assume that, in part A, you determined the slope of your Arrhenius plot to...
QUESTION 3 Assume that, in part A, you determined the slope of your Arrhenius plot to be 6,662 K. Calculate the corresponding activation energy (Ea) in kj/mol corresponding to this value. Report your answer to three (3) significant figures. 1 points Save Answer
1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for...
1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for the reaction increases from 93.5 M-1s-1 at 497.7 K to 1349.3 M-1s-1 at 636.7 K. do not include units, but make sure your answer is in kJ/mol! 2) A chemist constructs a plot of ln k vs. 1/T for a chemical reaction. The slope of the trendline for the data is -746 K. What is the activation energy for this reaction in kJ/mol? R...
first create a graph to solve the arrhenius equation for activation energy also need the graph...
first create a graph to solve the arrhenius equation for activation
energy
also need the graph please
Ymx Part 2 Calculations lnk=-Ea R .) + constant 1. Using the slope of the line of the Arrhenius plot, calculate the activation energy for the iodination of acetone in kJ/mol. Show all work for complete credit. T= 285, IS Temperature, K 205.15 296.15 293.15 296.15 301.15 305.15 IT,K") * 35|410" 3.xio” 3.46310 23.38x10$ 3.82x16° 3.28x101 Imela LM R. M 'S 179x10 1.656x16...
*****Help me find Ea in j/moles with the slope of -5056.2!! Experiment 4 CHM 112 8....
*****Help me find Ea in j/moles with the slope of
-5056.2!!
Experiment 4 CHM 112 8. Use the following data to prepare an Arrhenius plot to determine activation energy. Follow the excel directions in the procedure section of this lab. a. Use the concentrations from mixture 1 in question 1 to calculate the rate constant, k b. Complete the rest of the table. c. in excel, plot Ink) vs 1/Temp. Use the graph to determine the slope and then the...
question 5,6 part 1 and 2 please Question #5 Here are the relevant data to determine the activation energy of the...
question 5,6 part 1 and 2 please
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction. -3628 kl/mol Submit Please enter your results to the correct precision. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S2032 Jinitial Initial...
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate...
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction? 83 kJ/mol Submit This value is not correct. Please check your calculations and try again. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S203 initial Initial Rate .0023 M...
Question 24 (1 point) The graph below shows the results of an Arrhenius plot for the reaction 2 N2O(g) --> 4 NO2(g) + O2(g) In(k) vs. 1/1 In(k) (k in units of s.1) slope-1.24x104 K intercept=315 -14 0.0026 0.0028 0.003 0.0032 0.0034 Т (1/к) Which of the following most correctly describes the activation energy and frequency factor for this reaction? Ea-1.03x102 kJ mol 1 A-3.30x1031 - 1 Ea=-1.24x104 kJ mol-1, A=31.5 s -1 O Ea-1.03x108 kJ mol-1 A-4.79x1013 5-1 Ea=1.03x102...
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 y=-11624x + 32.055 R2 = 1 2 In k -3 -5 -6 0.0028 0.0029 0.0032 0.0033 0.003 0.0031 1/T (1/K) -96654 J/mol +96654 J/mol - 11624 J/mol +11624 J/mol -32.055 J/mol +32.055 J/mol
Examine the graph below and determine the value of the energy of activation for the chemical process. 0 -1 y = -11624x + 32.055 R2 = 1 -2 In k 3 -4 -5 -6 0.0028 0.0029 0.003 0.0031 0.0032 0.0033 1/T (1/K) -32.055 J/mol +32.055 J/mol -96654 J/mol +11624 J/mol - 11624 J/mol +96654 J/mol
Help with the work please!!
Question 3 0/3 pts An Arrhenius plot has a slope of -13,796 K and an intercept of 6.72. What is the activation energy in kJ/mol? Report your answer to three significant figures. 20 50 er 115 margin of error +/- 2%
QUESTION 3 Assume that, in part A, you determined the slope of your Arrhenius plot to be 6,662 K. Calculate the corresponding activation energy (Ea) in kj/mol corresponding to this value. Report your answer to three (3) significant figures. 1 points Save Answer
first create a graph to solve the arrhenius equation for activation
energy
also need the graph please
Ymx Part 2 Calculations lnk=-Ea R .) + constant 1. Using the slope of the line of the Arrhenius plot, calculate the activation energy for the iodination of acetone in kJ/mol. Show all work for complete credit. T= 285, IS Temperature, K 205.15 296.15 293.15 296.15 301.15 305.15 IT,K") * 35|410" 3.xio” 3.46310 23.38x10$ 3.82x16° 3.28x101 Imela LM R. M 'S 179x10 1.656x16...
*****Help me find Ea in j/moles with the slope of
-5056.2!!
Experiment 4 CHM 112 8. Use the following data to prepare an Arrhenius plot to determine activation energy. Follow the excel directions in the procedure section of this lab. a. Use the concentrations from mixture 1 in question 1 to calculate the rate constant, k b. Complete the rest of the table. c. in excel, plot Ink) vs 1/Temp. Use the graph to determine the slope and then the...
question 5,6 part 1 and 2 please
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction. -3628 kl/mol Submit Please enter your results to the correct precision. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S2032 Jinitial Initial...
Question #5 Here are the relevant data to determine the activation energy of the reaction. Rate constant (units not shown) Temperature (K) .13 293 0.11 308 Use the data above to determine the activation energy of the reaction? 83 kJ/mol Submit This value is not correct. Please check your calculations and try again. Question #6 Here are your data for trial of Lab 7 (the trial at room temperature without the catalyst): [103 initial (S203 initial Initial Rate .0023 M...
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