Question

An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8,000 g and an area of 5.00 cm2 and is free to slide up and down, keeping the pressure of the gas constant. (a) How much work is done on the gas as the temperature of 0.130 mol of the gas is raised from 15.0°C to 350°C? (b) What does the sign of your answer to part (a) indicate? The surroundings do positive work on the gas. There is no work done, by the gas or the surroundings. The gas does positive work on its surroundings. Need Help? Read It Submit Answer (-/20 Points] DETAILS SERCP11 12.3.P.011. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A balloon holding 4.50 moles of oxygen (0) gas absorbs 875 ] of thermal energy while doing 117 ] of work expanding to a larger volume. HINT (a) Find the change in the balloon's internal energy in J). j (b) Calculate the change in temperature of the gas (in K). Need Help? Read it Watch It [-120 points) DETAILS SERCP11 12.4.P.031. MY NOTES ASK YOUR TEACHER A gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m and then expands at constant pressure to a volume of 3.00 m before returning to its initial state as shown in the figure below. How much work is done in one cycle? k] P (atm) 6.00 4.00 2.00 -V (m) 1.00 2.00 3.00 Need Help? Read It

Answer 1

Amswer Given that (A2) U maag, A5 cm, n=0,130 mol. Ti=15°C, T2= 350°C caj 8K9, A: 5cm Ti TIF 288K, Tp=T2 = 623K know that From ideal gas equation PV=nRT VA wa - Spav=-P (4-V:) Vi PV=nRTi » (0 PV = nRTE (2) From (1) and(2) P Wi-Vf) = nR(Ti-Tf) - P(-V) = RR(TI-TO) W = nR (Ti-Te) -0,138.314 x(288-623) W=-362.07 JC-362J WE-3621) blaj The sw surroundings do poutine work on cscanned with CamScanner thuga

(2) Given that n=4.50 moles Q- 875J WF-117J( work done on gays of thermodynamics AUF Qtw 875-117 (a) uring ܢܝܢܩܐ mer OU= 7580 change in internal engrgy is 758] (b) ule know that DU=NC NOT Helium, monatomic gay = R. OT- DU DU mcv 200 3 NR -2x758 3x4,5 x 8,314 [OT = 13.5K change in temperature is 13.55K nxBR] CSScanned with CamScanner

(3) Given that Pi= a atm Pf= c Gatm constant' Volume(V) = amo Platm) Vf=3 m² P=6-2)=4x1.013X105pa c. 4 2 2 33 V moj 2 work is done in one cycle W= Spov WE Ź (6-3)(3-1) WS 4X105J CS$canned with CamScanner