Question

According to a recent poll, 29% of adults in a certain area have high levels of cholesterol. They report that such elevated levels 'could be financially devastating to the regions healthcare system and are a major concern to health insurance providers. Assume the standard deviation from the recent studies is accurate and known. According to recent studies, cholesterol levels in healthy adults from the area average about 206 mg/dL, with a standard deviation of about 25 mg/dL, and are roughly Normally distributed. If the cholesterol levels of a sample of 44 healthy adults from the region is taken, answer parts (a) through (d). (a) What is the probability that the mean cholesterol level of the sample will be no more than 2067 Plys 206)=L(Round to three decimal places as needed.) (b) What is the probability that the mean cholesterol level of the sample will be between 201 and 2117 P(201<ý<211)- (Round to three decimal places as needed.) (c) What is the probability that the mean cholesterol level of the sample will be less than 1967 Plý<196) = (Round to three decimal places as needed.) (d) What is the probability that the mean cholesterol level of the sample will be greater than 218? Ply>218) - (Round to three decimal places as needed.)

Answer 1

Sall Criven values are na 44, M = 206, 5=25 @ "P(5 €206) = P12c you) =P/z. 206-206) 25/5 = P(220) P (J 6 206)- 0.5 6 P/201 <ýc211) = P(5 ( 211 ) - P (3 (201) =P(221:366) -/76-13266) 0.9077 - 010923 PL 201 C9 C211) = 0.8154 © Plū (196) = P(Z < 196-206 ) 2514 = P(2.2.6533) PLJ <196) - 0.00u @ Pl 5 > 218) =1-P 15 2218 ) 218-206 21- P(Z < 5 var = 1-(3.1840) - 1-0.9093 p(17218) - 0.0007