F=K*q1q2/r^2
600 = 9*10^9*2*-2/r^2
600 = -36*10^9/r^2
r^2 = -36*10^9/600
r = sqrt(60*10^-6)
r = 7 745.966
An average human weighs about 600 N If two such generic humans each carried 2.0 coulomb...
An average human weighs about 600 N . If two such generic humans each carried 2.0 C coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 600 N weight?
Two men each weigh 650 N. One man carries + 1.0 C of excess charge, the other -1.0 C of excess charge. How far apart must they be for their electric attraction to equal 650 N?
8. Two men each weigh 650 N. One man carries +1.0 C of excess charge, the other -1.0 C of (1 point) excess charge. How far apart must they be for their electric attraction to equal 650 N? 1.0 km O3.3 km O2.5 km O3.7 km
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in newtons per coulomb to three significant figures Two point charges are placed on the x axis. (Figure 1) The first charge, q 8.00 nC, is placed a distance 16.0 Im from the origin along the positive x axis; the second charge, g2 -6.00 nC, is placed a distance 9.00 m from the origin along the negative x axis Hints EA,EA0,0.300 N/C Submit My Answers Give Up Correct Figure 1 of 1 Part B An unknown additional charge q3 is...
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Constants Part A Two charged dust particles exert a force of 4.5x10-2 N on each other. What will be the force if they are moved so they are only one-eighth as far apart? Express your answer using two significant figures F Value Units Submit Provide Feedback <Return to Assignment