Sol. A :- We have to calculate Electric field at Origin due to charge q1 and q2.
Net electric field at origin Etotal = E1 + E2
Where E1 and E2 are electric field due to charge q1 and q2 respectively.
First we will calculate E1 = 11
We have given in question q1 = 8nC
And r1 = 0 + 0 - 16 - 0 = -16 + 0
So magnitude of r1 = 16
Putting in formula we get E1 = = 9/32()
Similarly, now calculating E2,
We have q2= 6nC
and r2= 9
Putting in formula E2 = Kq2r2/
E2 =
Which is E2 = 2/3
Now Etotal = E1 + E2 = (2/3 - 9/32) = 37/96
So EOX= 37/96 and EOY = 0 ( because there is no y component in Etotal)
Sol. B :- Now we have q2 = -6nC
So E2 = 2/3 ()
There is no change in E1 because q1 is same.
So EOX = (2/3 + 9/32)()
EOX = 91/96 ()
EOY is still zero as no component of y in ETotal.
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