Question

Two point charges are placed on the x axis. (Figure 1)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis. Part A Part complete Calculate the electric field at point A, located at coordinates (0 m, 12.0 m ). Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. View Available Hint(s) EAx,EAy = 0,0.300 N/C SubmitPrevious Answers Correct Part B An unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of q3 needed to make the total electric field at point A equal to zero. Express your answer in nanocoulombs to three significant figures. View Available Hint(s) q3 = nC Submit

Answer 1

E,sin E^sino. E,cose (0 m. 12 0 72 (0 m, 0 m) (-9 m, 0 m) (I6 m, 0 m) The distance is 160)(12-0) =20m The angle is 12 16 tan 36870 The magnitude of the electric field iS kq, 7. 9x10°)(8x10-9 (20)* 0.17 N/C Express the electric field Ej in vector form as follows E E cos (-)+Esin a (j) -(0.18)cos (36.87)i)+(0.18) (sin 36.87)(j) -0.144+0.108j The distance is 210-(-9)(12-0 -15 m The angle is 12 9 53.13 The magnitude of the electric field is

kq2 (9x10') (6x10) (15) 0.24 N/C Express the electric field Ej in vector form as follows E,-E, cos a (i)-E2 sin a (j) (0.24)cos(53.13)()(0.24)(sin 53.13)(j) 0.144i+0.192j The total magnetic field is E0.144i +0.108 j + 0.144i+ 0.192j - Oi +0.3j Thex component of electric field The y component of electric field E,-0.3 NC The magnitude of magnetic field is The charge is kqs (03)(3) (9x109) 0.3x 10 -9 - 0.3 nC