6. Given the following equations:
(i) 3 A2+ + 2 D → 3 A + 2 D3+
(ii) D + 3 B+ → D3+ + 3 B
(iii) 2 C + 3 A2+ → 2 C3+ + 3 A
Arrange the elements A, B, C, and D from the strongest to weakest
reducing agent.
In the reaction i) D is reducing A2+ to A and itself oxidized to D3+
In the reaction ii) D is reducing B+ to B and itself oxidized to D3+
In the reaction iii) C is reducing A2+ to A and itself oxidized to C3+
so from these three reactions, it can be said that D is the strongest reducing agent and A is the weakest reducing agent.
So, the order is
D>C>B>A
Given the following equations: (i) A + C2+ → A2+ + C goes (ii) 2 D3+ + 3 A → 2 D + 3 A2+ doesn't go (iii) C2+ + B → C + B2+ doesn't go Arrange the elements A, B, C, and D from the strongest to weakest reducing agent.
6. Given the following equations: (i) C + A3+ → C++ A (ii) 3 D + C+ 3 D* + C (iii) B + 2 D B 2+ + 2 D goes Arrange the elements A, B, C, and D from the strongest to weakest reducing agent. goes goes
6. Given the following equations: (i) C++A --> C+A doesn't go (ii) D + 3 C --> D+ + 3C goes (iii) 3 B + D --> 3 B +D goes Arrange the elements A, B, C, and D from the strongest to weakest reducing agent.
Given the following equations: (i) B2+ + C --> B + C2+ doesn't go (ii) D+ B2+ --> D2+ + B (iii) 2 A3+ + 3D --> 2 A+ 3 D2+ doesn't go Arrange the elements A, B, C, and D from the strongest to weakest reducing agent. goes
Arrange the following three bases in order of increasing base strength. NH CH3OH ОСН; II I III a. (Weakest base) I < II < III (Strongest base) b. (Weakest base) I < III < II (Strongest base) c. (Weakest base) II < I < III (Strongest base) d. (Weakest base) II < III < I (Strongest base) e. (Weakest base) III < II <I (Strongest base) f. (Weakest base) III < I< II (Strongest base)
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