Question

(10 pts) A flexible ves volume be wiven the person, the Ce contains 53 Lofyas where 16 atm. Who . What will the r constant Mee prawem 53L I weatm =0.61 atm 0.03 0.4 -) (5.3) 0.60(Y) ㅠ a =1 48 -0.ull T T 17 o ur x an 3 : luu 13(0.6) = 164.5310.01) = 101.5831203 = 0.4 n3K 2036 ...いろ and we has a volume of 3.92 mly what (10 pts) A sample of nitrogen gas at volume at 0°C and 760mmHg? nuox 2n3=20n480 (140)(x). 391k 1000) (3.92 " = anok 3.9am 291 40 mm Hg = 10.2 = n.8 2n3K nuommiiga 2017

Answer 1

The formula which is used is:

Where 1, 2 represent initial and final states respectively,

P = Pressure,V = Volume , T = Temperature

When using the equation,ensure that the units of pressure volume and temperature are same on both sides. The unit of temperature which should be used is K.

1^st question:

The temperature remains constant. So T₁ = T₂

Initially, 53L of gas is present at 1.6 atm. So, V₁ = 53L and P₁ = 1.6atm

Final volume =V₂ = need to find.

Final pressure is 0.16atm = P₂

Putting in the formula :

1. batm x 53L Oolbalm X V₂ T2 71-72: 1.6 alm x 53L 0016 atm = Vz T 1.6 am 5L Oolbatm - Heat x look atm 532. = 530L. (ans) Answer 2: Here, 'initially, So, gas is at 18c, 760mm Hg, 3.92 mb. Pq = 760-mm Hg = 3.92 mL 14 - 18°C = (18+273)K = 2918. 11 11 Final state : ₂ = to find Iz = Pc = (0+273)* = 273K P2 = 760 mm Hg Putting in formula: 760mm Hg x 3.92mL 760 mm Hg X V2 2916 ...273k or = 760mmHg a 3.92 mL x 760 yam Hg 3.67mL. (ans) 213k 291k =