Question

Question 8 1pts A ball is thrown vertically upward with an initial speed of 20 m/s. Two seconds later a stone is thrown vertically from the same initial height as the ball) with an initial speed of 24 m/s. At what height above the release point will the ball and stone pass each other? The acceleration is 9.8 m/s in the downwards direction 17 m E E 21 m

Answer 1

que after 2 seconds. let in be the 2'na wachh stone each other.. . height where & the ball the pass St, na position of stone at time t o .. =position of ball at time (t +2) so, for the ball . ha v (+12) - 2 g (+-+2)? a for the store na uz (t) - zgt²

Vo (442) a (x+2) = vzt - 92 +² =) 4. (4+2) - ļt-29 + - 29 = vzt - se? 7 vit-vzt-agt +24,-29=0 = (v.-v₂-29)+ = 29-v.) to 269-VU IV. -V -23) ginen; vi= 20mis, v₂ = 24 mis a g 29.8 5) to 269.8 – 20) (20-24 - 29.8 >> tz is soy na '24 (2) - 6419.00 ( 17.084487221m Than7 m.capovor) so, Ist option is connect.