Consider the circuit 39.8 V 36.8 Ω 19.9 V 5.46 Ω 16.6 Ω Find the current...

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Question

Answer 1

Answer #1

Soluom. 39.8 36 8 6 Pr 9-9 5.46J Appl^ kvL in loop A BCFA 39-3 - 36.8 5-46-14.9- o -) 5.4612-36.8T| +19.9 e.

Answer 2

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