007 10.0 points Consider the circuit in the figure. 6.4 Ω 3.3 Ω - 6.4 Ω...

Question

Question

Answer 1

Answer #1

I = 5.07 3.9 I = 1.3 A In fig 1 loop ABEFGHCDA apply KuL in I t 10 0 I3 I 3.3 I 12 = 0 1.3 + 10 Iz + 3.3x2.1 -120 =o lo Iz +

Answer 2

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