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12) On a cold day, you take in 4.2 L of air into your lungs at a temperature of 0
12) when pressure is constant
V1/T1 = V2/T2...
4.2/273 = V2/(273+37)...
V2 = 4.2*310/273 = 4.8 L..
13) from P*V = n*R*T...
n = P*V/(R*T) = 101.3**4.2/(8.314*300)=0.17 moles...
here R is universal gas constant = 8.314 L kPa K^-1 mol^-1
The volume of air is proportional to the absolute
temperature.
T1 = 273 degrees
T2= 310 degrees,
So V2/V1 = 310/273
V1 = 310 / 273 * 4.2 L
= 4.8
partB
just use ideal gas law:
pV = nRT
101300*(4.20/1000) = n*8.314*(27+273)
n = 0.17 mole
partB
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