Question

USUTELH My Courses Module 5 > Module 5 Homework Chapter 3 part 2 Module 5 Homework Chapter 3 part 2 Problem 3.29 A shot-putter throws the "shor (mass = 73 kg) with an initial speed of 14.7 m/s at a 38.0° angle to the horizontal Part A Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.10 m above the groun Express your answer using three significant figures and include the appropriate units. O"! Å OO? Value Units Submit Request Answer Provide Feedback Type here to search

Answer 1

u=14•7 mle 12.10m mm Uy - - - - - - - - --- - - - --- Ground D SOI y = USin 38° = 14.7 X 0.615 x 9.04 m/s. Now, To Calculate time (T) taken by Shot to reach from Point À to Point G. Let to be the time taken by Shot to travel 'Ato 2 u sind 2x9.04 So, z = - n 1.84 Sec. go 8 Now, det 'zz be the time taken to travel from 'B' to ć' 2.10 = 9.04 Zz + 1 x. 8 x 7 [s=uz + 1 az2] 4.9 % + 9.04 2₂ - 2.10 =0 – – 9.04 ± √ (8.04)² + 4x4•9 +2:10 2x 4.9 -9.04 neglecting I 11.08 = 0.208 sec _ve zime 9.8 so, Total time of flight (T) = Z,tt2 = 2.04 sec. Now, Ux = u coso = u cos 38° = 14.7 X 0.78 ~ 11:46m/s. so total distance travelled before it reaches c' Point is unXT =(11.466 2:04)m = 23.39 m Ans. so, AX