Question

A 2690 kg unmanned space probe is moving in a straight line at a constant speed of 198 m/s. Control rockets on the space probe execute a burn in which a thrust of 4520 N acts for 62.5 s. (a) What is the change in the magnitude of the probe's linear momentum if the thrust is directed in the forward direction, so as to slow the probe? (b) What is the change in kinetic energy under the same condition? Assume that the mass of the ejected burn products is negligible compared to the mass of the space probe.

Answer 1

Given,

Mass(m) = 2690 kg

F = 4520 N

Given, Mass(m) = 2690 kg F = 4520 N Delta t = 62.5 sec We know that: change in Momentum (Delta P) = F times Delta t We observed that, Change in Momentum of the probe would be 2.825 times 10^5 N.sec. The direction of thrust respect to the velocity will not matter for this problem. Therefore, the change in momentum of the probe is equal in the every case for the thrust is backward, forward and sideways.

We know that:

We observed that, Change in Momentum of the probe would be .

The direction of thrust respect to the velocity will not matter for this problem. Therefore, the change in momentum of the probe is equal in the every case for the thrust is backward, forward and sideways.