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5. For the previous problem write an equation of its oscillatory motion using a sine or cosine function and assuming that the


4. A mass of 1.80 kg is attached to a horizontal spring with a spring constant of 450 N/m. There is no friction between the m
4. m² 1.80kg K = 450 N/m amplitude A = 14 cm angular vel. = W = √k/m = 450 - V 230 vaal is a) velocity ra WA?n? v=1250 [142-7
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Answer #1

♡ X(t) = (14cm)cos (61) W = 18.81 roedffee X(t) = 14cm cas 15.61 X 0.26) 14 cm Cas (4.11.2012 = 14 cm x -0.57 x (t) = 17:90 c

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