Question

9. Mars has a mass of 6.40 x 1023 kg and a radius of 3.40 x 10° meters. A projectile is shot straight up with an initial velocity of 22.2 m/sec from the surface of Mars a) Find the total time the projectile is in the air. b) Find the velocity of the projectile at 10 seconds. c) Find the maximum height of the projectile. Find the height of the projectile above ground at 10 seconds. d)

Answer 1

Given That mass M = 6.40 times 10^23 kg Radius of marks R = 3.40 times 10^6 meters accleration due to gravity on the surface of mars g = GM/R^2 where G = Gravitational constant = 6.67 * 10^- 11 Nm^2/kg so, g = 3.69 m/s^2 intital velocity of the projectle U = 22.2 m/s so, a total time the projectle is in the air t = 241g = 12s b time of assent = times of desent at time t = 10s itin free fall state after freeall t = 105.6s = 4s velocity of The project at 10 seconds i.e velocity of the project after 4s of freeall \r\n V = V_0 + gt where V_0 = 0 m/s so, V = 14.76 m/s c maxim height of the projectle H = U2/2g = 66.78m d Distance travelled free all state in 4s is S = V_0 t + (1/2)gt^2 = 29.52m height of the projectle ground at 10 seconds = H.S = 37.26m