Question

PART B: OPAMP as a non-inverting amplifier
a) Implement the following circuit using the LM741 and energize the integrated circuit 741 with + 15v and -15v. In addition, feed the circuit with a 1 Vpp and 1KHz sinusoidal signal. Values: R2 = 10kΩ, R1 = 1KΩ

R2 -15V U2 R1 + 741 LD V 15V (+2

b) Obtain the graph of the output voltage and the input voltage. Explain the differences between the graphs and determine the circuit gain.

c) Change the R2 resistor with a 5.1k Ω resistor. Obtain again the graph of output voltage and input voltage. What happens to the output voltage of the circuit? Explain

d) What differences did you observe with respect to the inverting amplifier implemented in the previous circuit?

Answer 1

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b) Output and input graphs when R2 = 10K

Tek M Pos: -640us MEASURE CH1 PK-Fk 1V CH2 Pk-Pk CH1 None CH1 None CH1 None CH1 500mV CH2 2V M 500us CH1/OV

C) Output and input graphs when R2 = 5.1K

Tek M Pos: -160us MEASURE CH1 Pk-Fk 1V CH2 Pk-Pk 6.11V CH1 None CH1 None CHI None CH1 500mV CH2 2V M Ims CH2 6. 6V

The difference between the graphs is Channel-! graph is input voltage and Channel-2 graph is output Voltage ... there the output Voltage is amplified So, the output Voltage is more than the input Voltage . Vin = 1 Vp-p. Vout='ll VP-P = circuit gain = out = !1W To circuit gain. 211)

c). If we change the value of resistor R from lokoh to a 5.1K2, the output Voltage decreases Compared to the output voltage we got with lok2 resister Since gain of the circuit is Site = 1 + 5* = 61 Gain decreases from 11 to 6/ Hence output Voltage decreases from Ilupup to 6.1 V p-p. d) This circuit is non-inverting amplifier circuit so both input and output are in the Same phase. (0°) But in the inverting amplifies input and output are in the opposite phase (180°) .