Question

11. 1/2 points Previous Answers ColFunPhys1 8.P.008. My Notes Ask Your Te. (a) What impulse must be imparted to a golf ball of mass 0.045 kg to give it a velocity of 46.1 m/s? 20745 N'S (b) If the golf club is in contact with the ball as it is accelerated over an interval of 1.21 cm, estimate the average force exerted on the ball by the club. 171.446 N X

Answer 1

Solution:

As We know that the average force on a body is equal to-

=change in momentum/time

So we need to calculate the time first.

Now from third equation of motion

V² =U² + 2as

So u =0 here hence

a = 46.1 x 46.1 × 100 / 2 x 1.21. ( cm into meter)

Now time v = u + at

So t = v/ a. = 46.1 x 2 x 1.21 / 46.1 x 46.1 x100.

t = 2 x 1.21 / 46.1 x 100. Sec

Now average force = impulse/time

So force = 2.0745 x 46.1 x 100 /2 x 1.21 = 3951.837 N