molecular mass of sulfuric acid is 98g. w/v% is given as 0.98%. thus molarity is calculated by taking volume of solution as 1L and by using following formula:
molarity= molar mass of sulfuric acid÷ w/v% × volume 1L
= 98÷0.98×1000
= 0.1 M
option a is correct
What is the Molarity(M) for a 0.98%(W/V) H2504(sulfuric acid) O 2.0.01 M O 3.10.0 M O...
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