Question

26a.) What are the magnitude and direction of the net magnetic force acting on the square loop? The current in the loop is Ii 30.0 A and the current in the wire is I: 15.0 A. Distances are a-10.0 cm, and d 12.0 cm The drawing show two long, thin wires that carry currents in the positive : direction. parallel to the z axis. The 50-A wire is in the x- y-e plane and is 4 m from the z axis. What is the total magnitude of the net magnetic field at the origin? The small picture is to help with the 3D visualization. Both wires ane 26b.) plane and is S m from the z axis. The 40-A wire is in the

Answer 1

F_net = mu_0 I_1 I_2/2 pi (d - a/z) times a = mu_0 I_1 I_2/2 pi (d + a/2) times a F = 2 times 10^-7 times 30 times 15 times 10 times [1/12 - 5 - 1/12 + 5] F = 7.56 times 10^-5 N direction: (towards the wire) B_1^rightarrow (due to 50 A) = mu_0 times 50 A/2 pi times 5m (- j^^) = -2 times 10^-6 j^^T B_2^rightarrow (due to 40 Delta) = mu_0 times 40 A/2 pi times 4 m (i^^) = 2 times 10^-6 i^^T Therefore B^rightarrow = B_1^rightarroe + B_2^rightarrow implies magnitude = squareroot (2 times 10^-6)^2 + (- 2 times 10^-6)^2 = 2.83 times 10^-6 N