Question

What is the most likely decay for the Mn-57 nucleus? Ideal N/Z ratios at. # 1-20 = 1 at. # 20-40 = 1.25 at. # 40-80 = 1.5 Select one: a a decay b. proton emission c. Y-ray emission d. B decay @ e. positron emission ALIEN WAR

Answer 1

- Geven Mn - 57 nucleus Z = 1 - 20 = 1 za 20740 = 1.25 23) 40-80 = 105. e Condetesis : as If z> 82 (too heavy) - Prediction :- Alpha decay. 6) Pf N/2 is too high (too many neutions, - Predictioni :- Bela decay . c) If N/Z es too low (too many protons) - Prediction PE or EC Mm- 57 Nowe, we hane = 32 neutrous Z - 25 neution will be 57 - 25 N . 32 1028. 25 96 for z= 20-40 ; N2 stable es 1 to 10 25 That means for atomic no. 20, we want the ratio to close to 1 while for atomic no. Соли tо 40 кве и аt Івише шлифе, be close to 1.25 Becauge аlома ишиви 14 85 (Cl 4 . 20) 4 tas de Num Lil le clou to 1 buu 1. 28 4 larger than 1. I too high i.e. too many neutrons) so condelion (6) as above ß decay. ☺ please date!