The kinetic order = 1
so ln(initial conc/final conc) = kt
K = rate constant
t = time = 75 min
Initial conc = a
decomposed amount = 19Xa /100
final concentration = 81 X a / 100
Hence ln(100 X a / 81 a) = k x 75
ln ( 100 / 81) = k X 75
ln 1.234 = k 75
0.210 / 75 = k
k = 15.80
k = 0.28 x10^-2 min^-1
Now for first order we know that
t1/2 = 0.693 / K
t1/2 = 0.693 / 0.0028 = 247.5 minutes
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