Question

Using the data above and the third trial listed below, calculate the average value for all three measurements Mass of 1^st sample g Mass of 2^nd sample g Mass of 3^rd sample 9.994 g Average of all 3 samples g If the density of water at 19.5 degree C is 0.99826 g/ml, what is the volume for the above average mass of water

Answer 1

4) 1e sample mass - mass (beaker + 1e sample) - mass dry beaker 1e sample mass - 40,110 g 30,123 g - 9,987 g 2nd sample mass mass (beaker 1° sample +2nd sample)- mass (beaker +1° sample) 2nd sample mass 50,234 g 40,110 g 10,124 g 1° sample mass +2ndsample mass 3rdsample mass 3 Average of all three sample 9,987 g +10,124 g +9,994 g 3 10,035 g Average of all three sample - 5) 1 ml Average volume - 10,035 g 10,035 g 0,99826 g - 10,052 ml

6) V sample^Vrequired 100 10,052 ml - 10,000 ml 10,000 ml 100 0,52% V. required It is a positive error 7) 1 ml 0,99826g 1ersample volume 9,987 g - 10,004ml e sample sample required 10,004 ml - 10,000 ml 10,000 ml % Error 1er 100 100 0,04% V. required 2nd sample volume 10,124 g - 10142 ml 0,99826g 10,142 ml - 10,000 ml 10,000 ml sample required %Error 2nd sample =' ' 100 = 1,42% required 1 ml 0,99826 g V sample-Vroqutred, 100 3rd sample volume 9,994 g - 10,011 ml 10,011 ml - 10,000 ml 10,000 ml requir %Error 3rd sample : sample ' 100-0,1190 required