Consider the activity series: ….. Mg > Al > Fe > Zn > H > Cu...
Consider the activity series: ….. Mg > Al > Fe > Zn > H > Cu > Ag > Au …… Which of the statements will be true? i. in a voltaic cell Ag/Fe, element Ag will serve as anode and Fe will be cathode ii. Al will oxidize Cu, Ag, Au iii. Fe will reduce H, Cu and Ag iv. Cu will oxidize Al and Mg v. H is a stronger oxidizing agent than Cu, Ag
A. i and ii
B. ii and iii
C. i , iv and v
D. iii and iv
E. iv and v
Homework Answers
Galvanic Measured Cell Equation for Anode Equation for Cathode Ecell Anode Reaction Cathode Reaction Cu-Zn @jcu-Mg...
Galvanic Measured Cell Equation for Anode Equation for Cathode Ecell Anode Reaction Cathode Reaction Cu-Zn @jcu-Mg M010 LL Sof Mane t Mu ?. (imus -ur.- 3) Cu-Fe Zn-M 5) Fe-Mg ?) Zn-Fe -A Write balanced equations for the six cell reactions 2 + Compare the sum of the Zn-Mg and Cu-Zn cell potentials with the Cu-Mg cell potential. Explain your result. Compare the sum of the Zn-Fe and Zn-Mg cell potentials with the Fe-Mg cell potential. Explain your result.
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Does the ordering of activity series Mg, Zn, Fe, Cu, Ag agree with the ionization energies...
Does the ordering of activity series Mg, Zn, Fe, Cu, Ag agree with
the ionization energies of the elements? Why or why not?
selecuul UI e vunum 14. Since the activity series describes the propensity for a metal to lose electrons one might think that ionization energies could predict the activity series. Ionization energies are measured in the gas phase and have the following values for the metals used in this laboratory: Reaction Ag (5) ► Agt (g) + 1...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
Table provided below for context Please answer all parts that you can. 1. Which electrochemical cell...
Table provided below for context
Please answer all parts that you can.
1. Which electrochemical cell had the greatest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 2. Which electrochemical cell had the smallest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 3. If the oxidation and reduction half-reactions are separated in a battery, this means the oxidizing agent is...
Question 3 6.66 pts The following half-cells are availble: (i) Ag (1.0M) 1 Ag (s) (ii)...
Question 3 6.66 pts The following half-cells are availble: (i) Ag (1.0M) 1 Ag (s) (ii) Zn2+ (1.0 M) | Zn (s) (iii) Cu2+ (1.0 M)Cu (s) (iv) Co2+ (1.0 M)Co (s) 0.7994 v -0.76 V 0.337 v -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode and...
1. Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the...
1. Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) a. Ag(I) and Zr(IV) Cathode: Anode: Ecell b. Cr(III) and Co(II) Cathode: Anode: Ecell c. In(III) and Au(III) Cathode: Anode: Ecell
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
please help answer question 4, a-f please using the data below from chart 1 objectives from...
please help answer question 4, a-f please
using the data below from chart 1
objectives from lab, thank you
DATA:CA y 3 Ay No3 Part I: Cell Potential of voltaic cells under standard conditions: cell CU CND2 #27 14.0m Give the half Half cell reaction at Combinations Oxidation Reduction E the anode and with [ion] takes place Theoretical takes place cathode. Write in M here here (V) above the arrow E c (V) if it is oxidation or reduction. |-0.340...
Galvanic Measured Cell Equation for Anode Equation for Cathode Ecell Anode Reaction Cathode Reaction Cu-Zn @jcu-Mg M010 LL Sof Mane t Mu ?. (imus -ur.- 3) Cu-Fe Zn-M 5) Fe-Mg ?) Zn-Fe -A Write balanced equations for the six cell reactions 2 + Compare the sum of the Zn-Mg and Cu-Zn cell potentials with the Cu-Mg cell potential. Explain your result. Compare the sum of the Zn-Fe and Zn-Mg cell potentials with the Fe-Mg cell potential. Explain your result.
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Does the ordering of activity series Mg, Zn, Fe, Cu, Ag agree with
the ionization energies of the elements? Why or why not?
selecuul UI e vunum 14. Since the activity series describes the propensity for a metal to lose electrons one might think that ionization energies could predict the activity series. Ionization energies are measured in the gas phase and have the following values for the metals used in this laboratory: Reaction Ag (5) ► Agt (g) + 1...
Table provided below for context
Please answer all parts that you can.
1. Which electrochemical cell had the greatest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 2. Which electrochemical cell had the smallest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 3. If the oxidation and reduction half-reactions are separated in a battery, this means the oxidizing agent is...
Question 3 6.66 pts The following half-cells are availble: (i) Ag (1.0M) 1 Ag (s) (ii) Zn2+ (1.0 M) | Zn (s) (iii) Cu2+ (1.0 M)Cu (s) (iv) Co2+ (1.0 M)Co (s) 0.7994 v -0.76 V 0.337 v -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode and...
please help answer question 4, a-f please
using the data below from chart 1
objectives from lab, thank you
DATA:CA y 3 Ay No3 Part I: Cell Potential of voltaic cells under standard conditions: cell CU CND2 #27 14.0m Give the half Half cell reaction at Combinations Oxidation Reduction E the anode and with [ion] takes place Theoretical takes place cathode. Write in M here here (V) above the arrow E c (V) if it is oxidation or reduction. |-0.340...
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