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Refer to the circuit diagram depicted in Figure 1 below 10245V 20 20V (3-4021 10 22 3.1 Figure 1 Determine the Thevenin equiv

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Thorder to find the Thevenin equivalent impedance we have to Short Circuit all independent sources A (3-34). lon F ZAB - ZTHI (3-j4) + 10x I-20/0 = 0 -) I = 1.405 + 30.432) A VH = 580 - 10.45 +200 - 10xI > VTH = -10<45° +20 - 10x (1.405+j0:432) - VT-10216 - I= 0.99 L-106.9° A we Covent through So, load Z is 0.992-106.9° A

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