Question

Problem Three atoms have the following electron configurations: (a) 1s2 252 2p6 3s2 3p1 (b) 1s2 252 2p6 3s2 3p5 (c) 1s2 252 2p6 352 3p6 4s1 Which of the three will have the largest IE1 ? Which will have the smallest 14 ?

Answer 1

(B) will have the largest ionisation energy. This is because B has 3p5 electrons, one less than that of the noble gas configuration. Due to this 5 electrons, the effective nuclear charge on the electrons is very high. Hence, the amount of energy required to remove the electron will be very high. Hence, B has the highest IE values.

(C) will have the lowest value of fourth IE. This is because after losing the fourth electron, C would acquire stable half filled 3p3 electronic configuration. Hence C will have the lowest IE4 .

Hope it helped.

Kindly rate if it helped and all the veryy best :)))