Question

The group_list function accepts a group name and a list of members, and returns a string with the format: group_name: member1, member2, … For example, group_list("g", ["a","b","c"]) returns "g: a, b, c". Fill in the gaps in this function to do that.

def group_list(group, users):
members=[]
members += "," .join(users)
  
return ("{}:{}".format(group,users))
print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

Answer 1

Please find the updated python code:

- Here, in the code we are using .join() which takes an iterable(in this case it is a List) and returns a String as a result, not an array.
i) So, I just removed the statement members=[]  from the code since it is of no use(You can keep this if you want But there won't be any error for this since anyhow in the next statement we are changing it).
ii) Also, I removed the appending symbol(+) because it will create an error saying Syntax error(Either you declare members as an array or as a string, both will create an error) Since you are getting a string as an output from the result of .join()

- Finally returning the modified string members not users along with the group as:
return ("{}:{}".format(group,members))
Since member is a list, It will simply again be the same as the input but with a semicolon in between group and users.

(I believe that you fully understand the code. If you still have any query, Feel free to drop me a comment below)

Program:

def group_list(group, users):
  
#Here the variable users is a list. so we are using join to take out each element from the list
# and join these elements with a comma(Since in the output there is a comma along with a space too)
members = ", " .join(users)
  
#Returing the string which consists of a variable group of string type as well as the members of string too
return ("{}: {}".format(group,members))
  
print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

main.py 4 1. def group_list(group, users): 2 3 #Here the variable users is a list. so we are using join to take out each element from the list # and join these elements with a comma(Since in the output there is a comma along with a space too) 5 6 members .join(users) 7 #Returing the string which consists of a variable group of string type as well as the members of string too 9 return ("{}: {}".format(group, members)) 10 11 print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # should be "Marketing: Mike, Karen, Jake, Tasha" 12 print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # should be "Engineering: Kim, Jay, Tom" 13 print(group_list("Users","")) # should be "Users:"

Output:

input Marketing: Mike, Karen, Jake, Tasha Engineering: Kim, Jay, Tom Users: ... Program finished with exit code o Press ENTER to exit console.

Hope this Helps!!!
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