Question

40. The amount of fill (weight of contents) put into a glass jar of Saskatoon jelly is normally distributed with a mean of 830 g and standard deviation of 10 g. Find the probability that a random sample of 24 jars has a mean weight between 825 and 833 g.

Answer 1

let x= Amount of fill put into a glass jar of Saskatoon jelly aund & follows hormal disth bution with mean Mo 8300=10 na 24. we need to compute, P(825<ÃL8B3) P/825-830 10 224 - old 833-830 lor $24, ipl -2.4495 cze 104697) & P(Z £1.497) - P (re-2.4495) = 0.9292-0.0072 = 0.922 — from standard normal table P (8252X2833) 6.922