What is the molarity of the resulting solution when 47.946 g of Mn(ClO4)2 · 6 H2O...

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Question

What is the molarity of the resulting solution when 47.946 g of Mn(ClO4)2 · 6 H2O are added to 250.0 mL of water?

Answer 1

Answer #1

Molar mass of Mn(ClO4)2.6H2O = 55 + (35.5 + 64)2 + 6(16+1+1) = 362 gm/mol

Number of moles of Mn(ClO4)2. 6H2O = 47.946/362 = 0.13244 moles

Molarity = Number of moles of Solute/Volume of Solution (in L)

=> 0.13244/ (250/1000)

=> 0.5297 M

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Answer 2

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