What is the molarity of the resulting solution when 39.627 g of Mn(ClO4)2 · 6 H2O...

Question

Question

What is the molarity of the resulting solution when 39.627 g of Mn(ClO₄)₂ · 6 H₂O are added to 550.0 mL of water?

Answer 1

Answer #1

Solution :-

Formula to calculate the molarity is as follows

molarity = moles of solute / volume in liter

550.0 ml * 1 L / 1000 ml = 0.550 L

now lets calculate moles of 39.627 g Mn(ClO4)2.6H2O

molar mass of Mn(ClO4)2.6H2O = 361.9248 g per mol

moles = mass / molar mass

moles = 39.627 g / 361.9248 g per mol = 0.1095 mol

now lets calculate molarity

molarity = 0.1095 mol / 0.550 L

= 0.199 M

Therefore the molarity of the solution is 0.199 M

Answer 2

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