Question

q3 please using matlab

zain Jo. Ø 73 3:45 • nering Q1: a function with the name "Area Circumference to calculate the area and circumference tput) of a rectangle. Define the inputs of this function as required. (6marks) Write a manuscript to solve the following system of equations based on (A]x] =[b]. Find x1, x2 4. (5 Marks) 2x1 + x2-03 + 2x4 = 5 4x1 +5x2-3x3 + 6x4 = 9 -2x1 +5x2 - 2.03 + 6x4 = 4 4x1 +11.02- 4.3 + 8.04 = 2 03: Having f(x) = 3x - 13x2 + 2x, Integratef from-3 to 2. Using three different methods. Also, the 2derivative of fat x=-4. (6 Marks) Q4: Write a Matlab manuscript to define the following: (6 Marks) 11 3 -2 1. A=1 3 3 1 0 7 2. A 3. Transpose of matrix "A" 4. D= the first raw of matrix"A" 5. Add column to matrix"A" with the values of 10,2,0, 25: a) Why it's not recommended to write Matlab codes without using clear all, close all, clc. b) Why it's not recommended to write your code on the command window directly (5 Ma Share Favorite Edit Delete More

Answer 1

QUESTION 3

% Method 1 using int function
clc
clear all
syms x
f = 3*x^6 - 13*x^2 +2*x;
a = int(f, -3, 2);
disp(double(a));

Exam2_001. m x coonWN Editor - Users\muhsin Exam2_001.m +2 ss. mx GetReParam.m x PrintRe. mx Method 1 using int function clc clear ali syms x f = 3*x^6 - 13*x^2 +2*x; a = int(1, -3, 2); disp (double (a)); Command Window 835.4762

% Method 2 using Octave equivalent
clc
clear all
syms x
c = [3 0 0 0 -13 2 0]; %Coefficients based on the equation
integral = polyint(c);
b = polyval(integral, 2) - polyval(integral, -3); %limits given to calculate integral
disp(double(b));

> co to UwN Editor - C:\Users\muhsin\Exam2_001.m 2 ss. mx GetReParam.m x PrintRe. mx Exam2_001. m x anonymous_fn. m x PrintReVar. mx Untitled9.m * Method 2 using Octave equivalent clc clear all syms x c = (3 0 0 0 -13 2 0]; Coefficients based on the equation integral = polyint (c); b = polyval (integral, 2) - polyval (integral, -3); limits given to calculate integral disp (double (b)); IIIIIII Command Window 835.4762 fx >>

%Method 3 using QUAD function
clc
clear all
F = @(x)3.*x.^6 - 13.*x.^2 +2.*x;
Result = quad(F,-3,2)

+2 ss.m x GetReParam.m x PrintRe.m x Exam2_001. m x anonymous_fn.m OU WNP $Method 3 using QUAD function clc clear ali F = @(x) 3. *x.^6 - 13.*x.^2 +2.*x; Result = quad (F,-3,2) Command Window Result = 835.4762

Double differentiation at x=4:

syms x
f = 3*x^6 - 13*x^2 +2*x;%Function
y=diff(f,2); %Second differenciation
Result=vpa(subs(y,x,4))%Getting value at 4

Jouw NP Editor - C:\Users\muhsın ditter.m +2 ss. mx GetReParam. mx PrintRe.m xExam2_001. mx anonymous_fn. mx PrintReVar. mx Untitledg. mx differ. mx - clc clear all syms x f = 3*x^6 - 13*x^2 +2*x; $Function y=diff (1,2); Second differenciation Result=vpa (subs(y,x, 4)) Getting value at 4 Command Window Result = 23014.0