Since Ba(OH)2 is a strong base so it will completely dissociate in aqueous solutionm as follows:
Ba(OH)2(s) Ba2+(aq) + 2OH- (aq)
Each Ba(OH)2 produces 2OH- , so for a 0.025 M solution, the concentration of hydroxide ion will be,
[OH- ] = 2 x 0.025 M = 0.05 M
By definition, pOH = - log[OH- ] = - log(0.05) = 1.3
then pH = 14.00 – 1.3 = 12.7 (ANSWER)
Determine the pH, the pOH, the [OH-] and [H+] of a 0.025M barium hydroxide solution.
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