Question

4. The stress element on the fuselage of an airplane shown below is Gx 400 MPa; Oy -300 MPa; and Txy 200 MPa (clockwise). a. Draw the initial stress element showing the stresses acting on it. b. Showing your X and Y coordinate points clearly, draw the complete Mohr's circle on the attached graphing paper From the Mohr's circle, determine Gmax, Omin, and Tmax c. d. Draw the complete principal stress element. Draw the maximum shear stress element. e. f. Calculate Omax, Gmin, and Tmax from the appropriate equations and compare with the values you determined from the Mohr's circle. Airplane fuselage showing the stress element.

PLEASE SHOW ALL STEPS!

Answer 1

Question ѕivеn еx = Чобре, а=3soMP4 exy = 200 Mp¢ (Clockwise) 6 element =-300Mpa din 2004 pe=exy x=400Mpa you * ☺ Mohols cicle point A = Lox, exy} poin) B= (og-exy) centre of pohrls circe is Mid point of AB c= Loxtoy, og

Now Telemax (400,200) tromax € (50,-) 5-Axis max omin Bezco 200) Ccotse, c = ,) ce (50,0) radius of Mohols circle RECA= CB= Coo-50)2 + 2002 R=403.11 MPG

I max = ouin- 0 = Maximum o = Minimum Principle strese principle stress mox = Distance oct CD - 50 + 963-1) °pek = c = 453° 1) Erе у This = = OE-R = Бо — чo3: 1) n="2= -353-11 МР, Р Ү emax = OF = " <F2002 CF P= 103-11 ос- 50 <ber = мозу-(56) Смех — 338 - 98 94co MP4

a orientation of principle plane tan20p = zexy ox-oy) = 2X 200 = 400 400-(-300) 700 20p = tant (2) cep= 14.87° = 144.87+go = 104.89 1998 ex J --353-13 Mp4 og T= 453

Moximum stress plane }<n 2 - - °x-a5) --C-106) 2*ху охоо «n20 = (-1) с = -40 25° =>-19 / 4х чоо-Р | Ф• 25° трех — чоор4

oppon, opis is given by this Қозрця elen = (3) = » « - Коозе) + ( Кло перео °ыхе 50+ ve3. 11 e-cx - 50+ (93-1| орех - 45 3 • 1) HP4 "n - 5 — це 3. 11 оніn -35 3» () Смех — PM-х – орі с | 53:11 + 353-11 | = 403. 11 mpa) Answer anex