Question

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E = 7.0 kJ/mol. If the rate constant of this - 1 - 1 reaction is 1.8 10° M s at 212.0 °C, what will the rate constant be at 301.0 °C? Round your answer to 2 significant digits. 1 - 1 k = | M is x 6 ?

Answer 1

Rate constant at 301°C is 2.35*10^8(MS)^-1.
4n this auestian, exe are to A2rhnius Eauetion 2Tate coustaut Ae ARThenius fector Take natuncal loy lota Sidle Eq Activation Energy JAT alRT RE4as condtuut lnk Ta Tenpereture 17 30, 14T ten pencuture T eauetion ti) -(ii) tn RTI AT Teniperature T eauation i tii) dn k In t -Eq RT2 LA is constuut tar given eelctian) Sultract Equation ti)rom iii) ln kz Ink 7 R lin to uux eaueitton iv to salve gaing the oralele we are we have 13Ctiveutton Energy (Ea) -1

AT temperature T212 c rate constant Ki z i,Y10 m s 273.15t 212 u85.15 K pt temberce turelT rate coustu ut T-574.15 K .314 3k1 mol 3011c) -1 RE

So, From eauation liv 314 3k1mor45.15K 574 15k %41.953 K 0.0003195 k7 1 8X10 M3 O 269 1-8X10% M-'s1 0.269 K2 1X10%MSST 1.308 X1.8 XIO MS k 2.35X10 MS