Given:
T1 = 181 oC
=(181+273)K
= 454 K
T2 = 241 oC
=(241+273)K
= 514 K
K1 = 2.5*10^3 M-1.s-1
Ea = 40 KJ/mol
= 40000 J/mol
use:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(K2/2.5*10^3) = (40000.0/8.314)*(1/454 - 1/514.0)
ln(K2/2.5*10^3) = 4811*(2.571*10^-4)
ln(K2/2.5*10^3) = 1.237
(K2/2.5*10^3) = e^(1.237)
(K2/2.5*10^3) = 3.445
K2 = 8.613*10^3 M-1.s-1
Answer: 8.6*10^3 M-1.s-1
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