5. A function f has Taylor series (at 0) f(x)=0+2x+ 4x2/2! + 3x3/3!+...
Assume f−1 exists. Find as much of the Taylor series of f−1 (at 0) as you can. (Since you only know the first few terms of the Taylor series for f, you can only figure out f−1.
(Hint: There are two ways of doing this problem. One is get the derivatives of f−1 from knowing the derivatives of f; we talked about the first derivative in January and higher derivatives can be found by implicit differentiation with the chain rule and the equation f−1(f(x)) = x. Another is to use the equation f−1(f(x)) = x, assume f−1 has a power series expansion with unknown coefficients cn, plug in for f(x), and try to solve for the cn. If you want to try a web search, this is called “Lagrange inversion,” but I’m not expecting you to understand any of the sources that come up.)
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5. A function f has Taylor series (at 0) f(x)=0+2x+ 4x2/2! + 3x3/3!+... Assume f−1 exists....
2. The Taylor series of the function f(x) = - iſ about x = 0 is given by (x − 2)(x2 – 1) 3 15 15 2. 63 4 F=3+ = x + x2 + x + x4 + ... (x − 2)(x2 - 1) 8 16 6 (a) (6 marks) Use the above Taylor series for f(x) = . T and Calcu- (x − 2)(x2 – 1) lus to find the Taylor series about x = 0 for g(x)...
Previous Problem Problem List Next Problem (1 point) Suppose that f(x) and g(x) are given by the power series f(x) 55x +3x2 + 3x3+... and g(x-643x + 4x2 + 3x3 + By multiplying power series, find the first few terms of the series for the product h(x) -f(x) .gx)cccx2 +c3 со 30 c115 C212x C39 Note: You can earn partial credit on this problem. Previous Problem Problem List Next Problem (1 point) Suppose that f(x) and g(x) are given by...
Given f(x) = 3x3 + 4x2 + 4x + 3. Find (-1)'0).
Only #4!!!! 3 Another Taylor Polynomial Let's compute another Taylor Series, and then call it a day. So let's look at the function f(x) = ln(1 + x), centered at a = 0. 3.1: Compute the first five derivatives of f(x). 3.2: Plug a = 0) into them (as well as the original function) to get f(n)(a) for n from 0 to 5. 3.3: Write down f(n)(a)(x-a)" n! 0,..., 5. Can you infer the general pattern? 3.4: Write down the...
2. Use Taylor series expansions to arrive at the expression 1 3 1 f'(x) h f(x)2f(xh) - f(x2h) 2 which we found in class using Lagrange polynomials 2. Use Taylor series expansions to arrive at the expression 1 3 1 f'(x) h f(x)2f(xh) - f(x2h) 2 which we found in class using Lagrange polynomials
2 1. The Taylor series for a function f about x =0 is given by k=1 Ikitt (a) Find f(")(). Show the work that leads to your answer. (b) Use the ratio test to find the radius of convergence of the Taylor series for f about x=0. c) Find the interval of convergence of the Taylor series of f. (a) Use the second-degree Taylor polynomial for f about x = 0 to approximate s(4)
3. Consider the function shown in the graph. Bob says that it has a Taylor series at a-2 that Why can't this possibly be the first terms of the Taylor series? begins 2 - (x-1) + .5(x-1)2+ y=f(x) 3. Consider the function shown in the graph. Bob says that it has a Taylor series at a-2 that Why can't this possibly be the first terms of the Taylor series? begins 2 - (x-1) + .5(x-1)2+ y=f(x)
Find the degree 3 Taylor polynomial T3(x) of the function f(x)=(7x+50)4/3 at a=2Find the second-degree Taylor polynomial for f(x)=4x2−7x+6 about x=0thank you! (:
(1 point) Consider a function f(x) that has a Taylor Series centred at x = -3 given by an(x + 3)" n=0 If the radius of convergence for this Taylor series is R = 4, then what can we say about the radius of convergence of the Power Series Š an -(x + 3)" ? no n=0 A. R= 2 4 OB.R = 6 OC. R = 4 OD. R = 24 O E. R= 8 F. It is impossible...
5. Let f(x)- arctan(x) (a) (3 marks) Find the Taylor series about a 0 for f(x). Hint: - arctan(x) - dx You may assume that the Taylor series for f(x) converges to f (x) for values of x in the interval of convergence (b) (3 marks) What is the radius of convergence of the Taylor series for f(x)? Show that the Taylor series converges at x-1. (c) (3 marks) Hence, write T as a series (d) (3 marks) Go to...