Solution) d = 3.1 m
Radius , r = (d/2) = (3.1/2) = 1.55 m
I1 = 110 kgm^2
w1 = 0.60 rev/s
m = 25 kg
M = 4m = 4×25 = 100 kg ( total mass of 4 children)
(A) New angular speed , V = ?
I2 = I1 + M(r^2)
I2 = 110 + 100(1.55^2)
I2 = 350.25 kgm^2
Applying conservation of angular momentum
(I1)(w1) = (I2)(w2)
(110)(0.60) = (350.25)(w2)
w2 = (110×0.60)/(350.25)
w2 = 0.188 rev/s
(B) delta K = ?
delta K = KEi - KEf
delta K = (1/2)(I1)(w1^2) - (1/2)(I2)(w2^2)
delta K = (1/2)(110)(0.60×2(pi))^2 - (1/2)(350.25) (0.188×2(pi))^2
delta K = 781 - 243.42 = 537.58 J
delta K = 5.37×10^(2) J
delta K = 5.4×10^(2) J
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