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cos2 θ The transformationPez, cos θ sin θ 2 gives the orthogonal projection of the vector,2 onto ortho cosesin θ sin2 θ | the
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Answer #1

By the problem description, the projection is

\begin{align*}P_{\frac{\pi}6}[1,6]^T&=\begin{pmatrix}\cos^2{\frac{\pi}6}&\cos{\frac{\pi}6}\sin{\frac{\pi}6}\\ \cos{\frac{\pi}6}\sin{\frac{\pi}6}&\sin^2{\frac{\pi}6}\end{pmatrix}\begin{pmatrix}1\\6\end{pmatrix}\\ &=\begin{pmatrix}{\frac 34}&{\frac{\sqrt 3}4}\\ {\frac{\sqrt 3}4}&{\frac 14}\end{pmatrix}\begin{pmatrix}1\\6\end{pmatrix}\\ &=\begin{pmatrix}{\frac{3+6\sqrt 3}4}\\ {\frac{6+\sqrt 3}4}\end{pmatrix}\end{align*}

Up to two decimal place, this is \begin{align*}\begin{pmatrix}3.35 & 1.93\end{pmatrix}^T\end{align*} .

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