Homework Answers
![South (DO); = 10.6 mole (Dolf = 2.9 mill dientim = 20 @# B052 = (ooi - Doy.] xdibution = (10.6-2-9) X20 154 mgle B0D3 = BODA](http://img.homeworklib.com/questions/cdba0870-5786-11eb-a717-339c087853a8.png?x-oss-process=image/resize,w_560)
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Q2. A BOD3 test was run and the results were: Dilution = 20 Initial DO =...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and a total Kjeldahl nitrogen content (TKN) of 35 mg/L. (a) (b) Find the ultimate carbonaceous oxygen demand (CBOD). Find the ultimate nitrogenous oxygen demand (NBOD). Find the total ultimate (or theoretical) oxygen demand (TBOD). Find the remaining BOD (nitrogenous plus carbonaceous) after five days have elapsed.
7. A BOD test is run using 100 mL of treated wastewater effluent mixed with 200...
7. A BOD test is run using 100 mL of treated wastewater effluent mixed with 200 mL of dilution water (containing no BOD). The initial DO of the mix is 9.0 mg/L After 5 days, the DO is 4.0 mg/L. After a long period of time, the DO is 2.0 mg/L, and it no longer seems to be dropping. Assume nitrification has been inhibited so that only carbonaceous BOD is measured (a) What is the 5-day BOD of the wastewater?...
De constant kiday"). 8. A standard BOD test is run using seeded dilution water. In one...
De constant kiday"). 8. A standard BOD test is run using seeded dilution water. In one bottle, the water sample is mixed with seeded dilution water giving a dilution of 1:30. Another bottle, the blank, contains just seeded dilution water. Both bottles begin the test with DO at the saturation value of 9.2 mg/L. After five days, the bottle containing waste has DO equal to 2.5 mg/L while that containing just seeded dilution water has DO equal to 8 mg/L....
Determination of BOD dilution
Consider the BOD data below (no dilution,no seed). a. What is the ultimate carbonaceous BOD? b. What might have caused the lag at the beginning of the test? c. Calculate k’, (the reaction rate constant). Day DO(mg/L) ~~ 0 8 1 8 3 75 6.5 7 6 15 ...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both,...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both, using laboratory DO data. a. For sample A, seeded BOD test was performed. The initial DO concentration in the BOD bottle, which was filled with 2 mL of sample and 298 mL of seeded dilution water, was 8.9 mg/L just after preparation. After an incubation period of five days, the final DO concentration was reported as 1.8 mg/L. Meanwhile, DO concentration in the seed...
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical for...
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical formula CsHisO&N. Using the following reactions: CoHisO&N606CO2 6H2ONHa NHs 202 NOs H2O (a) Find the theoretical carbonaceous oxygen demand CBOD (b) Find the nitrogenous oxygen demand NBOD (c) Find the total theoretical biochemical oxygen demand BOD 2. A sandy soil has a hydraulic conductivity of 6.1 x104 m/d, a hydraulic gradient of 0.00141, and porosity of 20%. (a)what is the Darcy velocity (b)what...
Question 1 (a) What is water quality? Why is water quality testing important? (b) Write down...
Question 1 (a) What is water quality? Why is water quality testing important? (b) Write down the name of two organizations responsible for setting water quality standard? (c) The dilution factor D for an unseeded mixture of wastewater is 0.04. The DO of the mixture is initially 8.0 mg/L, and after 5 days it has dropped to 1.5 mg/L. The reaction rate constant K has been found to be 0.21 day!. (1) What is the 5-day BOD of the waste?...
QUESTION1 A 15-mL sample is added to à 300-ml 8OD bottle. Dilution water is added to the sample bottle and the initi...
QUESTION1 A 15-mL sample is added to à 300-ml 8OD bottle. Dilution water is added to the sample bottle and the initial dissoved axygen concentration is measured as 8.5 mg/L. After the sample is sealed, the laboratory incorrectly takes a measurement of dissolved oxygen reading on day 6 of 3 mg/L. If the BOD reaction rate coefticient for the sample is 0.30/day, estimate what the 5-day BOD should have been QUESTION 2 A 15-mL sample is added to a 300-mL...
A BOD test is run with 150 mL of wastewater mixed with 150 mL of deionized...
A BOD test is run with 150 mL of wastewater mixed with 150 mL of deionized water. The initial DO = 8.5 mg/L, the DO after 5 days = 4.2 mg/L, and the DO ultimately levels off at 1.7 mg/L. Assume all nitrification has been inhibited and the temperature remains constant. a) Calculate the CBOD5 (y5, mg/L) b) Calculate the ultimate CBOD (Lo, mg/L) c) Calculate the CBOD remaining after 5 days (L5, mg/L) d) Calculate the deoxygenation rate constant...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and a total Kjeldahl nitrogen content (TKN) of 35 mg/L. (a) (b) Find the ultimate carbonaceous oxygen demand (CBOD). Find the ultimate nitrogenous oxygen demand (NBOD). Find the total ultimate (or theoretical) oxygen demand (TBOD). Find the remaining BOD (nitrogenous plus carbonaceous) after five days have elapsed.
7. A BOD test is run using 100 mL of treated wastewater effluent mixed with 200 mL of dilution water (containing no BOD). The initial DO of the mix is 9.0 mg/L After 5 days, the DO is 4.0 mg/L. After a long period of time, the DO is 2.0 mg/L, and it no longer seems to be dropping. Assume nitrification has been inhibited so that only carbonaceous BOD is measured (a) What is the 5-day BOD of the wastewater?...
De constant kiday"). 8. A standard BOD test is run using seeded dilution water. In one bottle, the water sample is mixed with seeded dilution water giving a dilution of 1:30. Another bottle, the blank, contains just seeded dilution water. Both bottles begin the test with DO at the saturation value of 9.2 mg/L. After five days, the bottle containing waste has DO equal to 2.5 mg/L while that containing just seeded dilution water has DO equal to 8 mg/L....
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
1. Some pond water contains 20.O mg/L of some algae, which can be represented by the chemical formula CsHisO&N. Using the following reactions: CoHisO&N606CO2 6H2ONHa NHs 202 NOs H2O (a) Find the theoretical carbonaceous oxygen demand CBOD (b) Find the nitrogenous oxygen demand NBOD (c) Find the total theoretical biochemical oxygen demand BOD 2. A sandy soil has a hydraulic conductivity of 6.1 x104 m/d, a hydraulic gradient of 0.00141, and porosity of 20%. (a)what is the Darcy velocity (b)what...
Question 1 (a) What is water quality? Why is water quality testing important? (b) Write down the name of two organizations responsible for setting water quality standard? (c) The dilution factor D for an unseeded mixture of wastewater is 0.04. The DO of the mixture is initially 8.0 mg/L, and after 5 days it has dropped to 1.5 mg/L. The reaction rate constant K has been found to be 0.21 day!. (1) What is the 5-day BOD of the waste?...
QUESTION1 A 15-mL sample is added to à 300-ml 8OD bottle. Dilution water is added to the sample bottle and the initial dissoved axygen concentration is measured as 8.5 mg/L. After the sample is sealed, the laboratory incorrectly takes a measurement of dissolved oxygen reading on day 6 of 3 mg/L. If the BOD reaction rate coefticient for the sample is 0.30/day, estimate what the 5-day BOD should have been QUESTION 2 A 15-mL sample is added to a 300-mL...
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