Question

Q2. A) Projectile motion (General launch angle): Select any one of the options as answer A football kicker is attempting a field goal from 44 m out. The ball is kicked and just clears the lower bar with a time of flight of 2.9 s. If the angle of the kick was 45°, what was the initial speed(Vo) of the ball, assuming no air resistance? a) 21.5 m/s b) 19.7 m/s c) 2.2 m/s d) 39 m/s (Hint: x-Xo = 44 m, 0 = 45° &t=2.9 s Use one of the general launch angle equations for X-direction to find initial velocity (V.)] Q2. B] Projectile motion (General launch angle]: Select any one of the options as answer A boy throws a rock with an initial velocity of 3.13 m/s at 30.0° above the horizontal. How long does it take for the rock to reach the maximum height of its trajectory if air resistance is negligibly small and g = 9.80 m/s2? a) 0.160 s b) 0.282 s c) 0.313 s d) 0.441 s (Hint: When the rock will be at the highest point of its trajectory, the y-component of velocity becomes zero (Y) = 0 m/s, 0 = 40° & initial velocity (V.) = 3.13 m/s. Use one of the general launch angle equations for Y-direction to find time(t) taken to reach maximum height]

Answer 1

Q2.A Given 0 = 450 x = 44m, t = 2.9 sec for horizontal motion x-%= Vocosot = 44 * Vo = 44 troso So Vo= 44 2.9 Cos45 2). 457 57 m/s ^ 2105 m/s So a Po correct answer. 82.B Recall ta time to reach maximam height. こ Nosino g - 3.13 x singo' = 0.15969 ~ 0.16 Sec 9.8 So w is correct answer