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8.9 A chain of mass m and length / lies on a horizontal table with a portion hanging over the edge of the table. The only for

BA m1 m2 Figure 8.8 Problem 194 THE FORMALISMS OF LAGRANGE AND HAMI

тодити 9. Ý - 2 y = 0 10. A, L = (m,1? + m213)ë, + m2ll2cos(@z – 0,) Öz. - m2!122 sin(@2 - 0,03 + (m 4 + m2l2)g sin 0, = 0 12


8.9.) A chain of mass m and length l lies on a horizontal table with a portion hanging over the edgeof the table. The only force acting on the system is the constant gravitational force in the negative y- direction. Set up and solve Lagrange's equation. Assume uniform mass density.
8.10.) a) Set up Lagrange's equations for the double pendulum (Figure 8.8).
b) Assume that the amplitudes are very small. Simplify the equations keeping only terms linear in the variables.

The third picture is the answers to the problems according to the textbook

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Answer #1

cartesian Cosdinates of m, & my are ! LX,y),=sing, -l4os). (4,4)=(4 sine, th sine,-lqces8;=blo102) to to tado-Ot V = -mgy=Mysimülasly for O IM2J&sinOz upfying-theuations Reeping the leading orda terms. D=(M,+m) ot M&ô7(m,+M)g8 0.There is a small error in the solution given in the attachment I have checked my answer from other books as well.

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