Question

1. Assume that you have solid NaCl and all the glassware in your lab drawer available to you. What mass of sodium chloride would you need to prepare 10.0 mL of a 1.0 M NaCl(aq) solution.

2. Using the solution you prepared in #1, how many mL would you need to prepare a 2.5 mL 0.10 M NaCl solution?

Answer 1

NACl

M = 1

V = 10 ml or 0.01 L

n = M*V = 1*10/1000 = 0.01 mol o fNaCl

MW = 58

mass = mol*MW = 0.01*58 = 0.58 grams of NaCl

2)

ml for

V = 2.5 ml of a 0.10

M1V1 = M2V2

V1 = M2/M1 * V2

V1 = 0.1/1 * 2.5 = 0.25 ml are needed of original mix