The pH of 0.50 M HClO is 3.91. Calculate the change in pH when 1.29 g...
The pH of 0.50 M HClO is 3.91. Calculate the change in pH when 1.29 g of NaClO is added to 18 mL of 0.50 M HClO. Ignore any changes in volume. The Ka value for HClO is 3.0 x 10-8.
Homework Answers
pH = pKa + log (salt) / (acid)
number of moles of NaClO = 1.29 / 74.44 = 0.01733 moles
concentration of NaClO = (1.29 / 74.44) * (1000/18) = 0.9627 mole / L
pH = pKa + log (salt) / (acid)
pH = -log(3 * 10^-8) + log (0.9627 / 0.5 )
pH = 7.807
chane in pH = 7.807 - 3.91 = 3.897
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