mixture of CH3COONa and CH3COOH act as acidic buffer
pH = pKa + log [CH3COONa]/[CH3COOH]
pKa = - log K = - log 1.8 x 10-5 = 4.74
[CH3COONa] = (0.91 / 82.03)(1000 / 11.1) = 0.999 M
[CH3COOH] = 0.50 M
pH = 4.74 + log [0.999]/[0.50]
pH = 4.74 + 0.30
pH = 5.04
pH change = 5.04 - 2.52 = 2.52
QUESTION 9 The pH of 0.50 M acetic acid is 2.52. Calculate the change in pH...
Calculate the pH when 1.03 g of CH3COONa (FW = 82.03 g/mol) is added to 36 mL of 0.500 M acetic acid, CH3COOH. Ignore any changes in volume. The Ka value for CH3COOH is 1.8 x 10-5.
Calculate the pH when 1.61 g of CH3COONa (FW = 82.03 g/mol) is added to 34 mL of 0.500 M acetic acid, CH3COOH. Ignore any changes in volume. The Ka value for CH3COOH is 1.8 x 10-5.
The pH of 0.50 M HClO is 3.91. Calculate the change in pH when 1.29 g of NaClO is added to 18 mL of 0.50 M HClO. Ignore any changes in volume. The Ka value for HClO is 3.0 x 10-8.
Calculate the pH after 4.0 mL of 0.50 M NaOH is added to 110.0 mL of a buffer made of 0.40 M CH3COOH and 0.50 M NaCH3COO. The Ka of acetic acid is 1.8 x 10.
Calculate the pH of a 0.50 M solution of sodium acetate (NaCH3COO) given that the Ka of acetic acid (CH3COOH) is 1.8 x 105, A 9.26 B.9.22 11.48 D.4.78 E. 2.52
QUESTION 4 Calculate the pH when 1.13 g of NaClO (FW = 74.44 g/mol) is added to 32.9 mL of 0.50 M HCIO. Ignore any changes in volume. The Ka value for HCIO IS 3.0 x 10-8 1 points Save Answer
7. Calculate the mass of sodium acetate (CH3COONa) that must be added to 1.00 L 0.450 M acetic acid (CH3COOH), Ka = 1.8 x 10 ) to form a pH = 5.00 buffer. Ka = 1.8 x 109.
please solve and show work! A buffer contains 0.50 M CH3COOH (acetic acid) and 0.50 M CH3COONa (sodium acetate). The pH of the buffer is 4.74. What is the pH after 0.10 mol of HCI is added to 1.00 liter of this buffer? A.5.57 B.4.74 C.4.38 D. 4.92 E.4.57
A 50.0 ml sample of 0.50 M acetic acid, ch3cooh is titrated with a 0.150 M NaOH solution. calculate the ph after 25.0 ml of the base have been added (ka=1.8x10^-5)
calculate the ph of a buffer solution that contains 1.5 M acetic acid (CH3COOH) and 0.3 M sodium acetate (CH3COONa) [Ka=1.8x10-5 for acetic acid]