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Please don't forgot to calculate the temperature at which the
reaction switches .
1. Given the...
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for...
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for each of the following reactions. (a) CH4(g) + H2O(g) equilibrium reaction arrow CO(g) + 3 H2(g); ?H° = +205.9 kJ, ?S° = +214.7 J/K ?G° 141.9 Correct: Your answer is correct. kJ K (b) CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g); ?H° = +179.2 kJ, ?S° = +160.2 J/K ?G° 131.5 Correct: Your answer is correct. kJ K
Consider the following reaction and the corresponding thermodynamic data to answer the next two problems. CaCO3...
Consider the following reaction and the corresponding thermodynamic data to answer the next two problems. CaCO3 (s) ( CaO (s) + CO2 (g) (Ho rxn = 179.2 kJ/mol; (So rxn = 160.2 J/mol K What can be stated regarding the spontaneity of this chemical reaction? a) This reaction is spontaneous at all temperatures. b) This reaction is spontaneous above 894K and non-spontaneous below 894 K. c) This reaction is spontaneous below 894 K and non-spontaneous above 894 K. d) This...
Question 19 Determine AGºrxn for the following reaction at 298 K. CaCO3(s) --- CaO(s) + CO2()...
Question 19 Determine AGºrxn for the following reaction at 298 K. CaCO3(s) --- CaO(s) + CO2() AH®= +179.2 kJ; A5°= +160.2 J/K -131.5 kJ +226.9 kJ +179.2 kJ -226.9 kJ +131.5 kJ
Consider the following reaction: CaCO3(s)→CaO(s)+CO2(g). Estimate ΔG∘ for this reaction at each of the following temperatures....
Consider the following reaction: CaCO3(s)→CaO(s)+CO2(g). Estimate ΔG∘ for this reaction at each of the following temperatures. (Assume that ΔH∘ and ΔS∘ do not change too much within the given temperature range.) Part A 315 K ΔG∘ Δ G ∘ = nothing kJ Part B 1085 K ΔG∘ Δ G ∘ = nothing kJ Part C 1465 K ΔG∘ Δ G ∘ = nothing kJ Part D Predict whether or not the reaction in part A will be spontaneous at 315...
spontaneous or nonspontaneous spontaneous or nonspontaneous spontaneous or nonspontaneous Consider the following reaction: CACO3(s) CaO (s)...
spontaneous or nonspontaneous
spontaneous or nonspontaneous
spontaneous or nonspontaneous
Consider the following reaction: CACO3(s) CaO (s) + CO2 (g). Estimate AG for this reaction at each of the following temperatures. (Assume that AH° and AS do not change too much within the given temperature range.) Part A 290 K Part B 1095 K Part C 1475 K
What temperature must the reaction be above in order to become spontaneous? CaCO3(s)CaO(s)+CO2(9) AHor (CaCO3)-1207.6 k]/mol...
What temperature must the reaction be above in order to become spontaneous? CaCO3(s)CaO(s)+CO2(9) AHor (CaCO3)-1207.6 k]/mol So (CaCO3) 91.7 J/mol K AHof (CaO)-35.09 kJ/mol S° (CaO) 38.2 J/mol K AHor (CO2)-393.51 kJ/mol So (CO2)213.74 J/mol K
The decomposition of calcium carbonate is given by the equation, CaCO3(s) →CaO(s) + CO2(g). Determine if...
The decomposition of calcium carbonate is given by the equation, CaCO3(s) →CaO(s) + CO2(g). Determine if the reaction is spontaneous at room temperature, given the following thermodynamics parameters: Δ? = 178 kJ/mol Δ? = 163 J/Kmol
part 1 answer is correct. Looking for #2 on this sheet with work please Verarbon dia...
part 1 answer is correct. Looking for #2 on this sheet with work
please
Verarbon dia Gibbs Free Energy & Predicting Spontaneity 1) The decomposition of calcium carbonate into calcium oxide and carbon dioxide (shown below) is not spontaneous at 298 K. CaCO (8) Cao(8) + Co.g) AH = +179 28 Using the data provided above, calculate the value of Great 298 K. 10- +160.29 179.2151005 AGO - DHOTOS I min hof amor AG° = 179200 Frei- 298(160.23imo) DGO=131460.45 sco=131.4605lmo...
(a) Choose all of the statements from below which correctly describe issues pertaining to the relationship...
(a) Choose all of the statements from below which correctly describe issues pertaining to the relationship between the emf of a reaction and its Gibbs free energy change. The Gibbs free energy change and emf values of a reaction have opposite algebraic signs (+ vs. -). A spontaneous reaction has a positive Gibbs free energy change and a negative emf. A Gibbs free energy change involves coulombs of substances whereas an emf involves moles of electrons. A coulomb of particles...
Exercise 17.62 Consider the following reaction: CaCO3(s)→CaO(s)+CO2(g). Estimate ΔG∘ for this reaction at each of the...
Exercise 17.62 Consider the following reaction: CaCO3(s)→CaO(s)+CO2(g). Estimate ΔG∘ for this reaction at each of the following temperatures. (Assume that ΔH∘ and ΔS∘ do not change too much within the given temperature range.) Part A 285 K ΔG∘ = 134 kJ SubmitMy AnswersGive Up Correct Part B 1095 K ΔG∘ = kJ SubmitMy AnswersGive Up Part C 1475 K ΔG∘ = −50.9 kJ SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part D Predict whether or not the reaction...
Question 19 Determine AGºrxn for the following reaction at 298 K. CaCO3(s) --- CaO(s) + CO2() AH®= +179.2 kJ; A5°= +160.2 J/K -131.5 kJ +226.9 kJ +179.2 kJ -226.9 kJ +131.5 kJ
spontaneous or nonspontaneous
spontaneous or nonspontaneous
spontaneous or nonspontaneous
Consider the following reaction: CACO3(s) CaO (s) + CO2 (g). Estimate AG for this reaction at each of the following temperatures. (Assume that AH° and AS do not change too much within the given temperature range.) Part A 290 K Part B 1095 K Part C 1475 K
What temperature must the reaction be above in order to become spontaneous? CaCO3(s)CaO(s)+CO2(9) AHor (CaCO3)-1207.6 k]/mol So (CaCO3) 91.7 J/mol K AHof (CaO)-35.09 kJ/mol S° (CaO) 38.2 J/mol K AHor (CO2)-393.51 kJ/mol So (CO2)213.74 J/mol K
part 1 answer is correct. Looking for #2 on this sheet with work
please
Verarbon dia Gibbs Free Energy & Predicting Spontaneity 1) The decomposition of calcium carbonate into calcium oxide and carbon dioxide (shown below) is not spontaneous at 298 K. CaCO (8) Cao(8) + Co.g) AH = +179 28 Using the data provided above, calculate the value of Great 298 K. 10- +160.29 179.2151005 AGO - DHOTOS I min hof amor AG° = 179200 Frei- 298(160.23imo) DGO=131460.45 sco=131.4605lmo...
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