Question 19 Determine AGºrxn for the following reaction at 298 K. CaCO3(s) --- CaO(s) + CO2()...
What temperature must the reaction be above in order to become spontaneous? CaCO3(s)CaO(s)+CO2(9) AHor (CaCO3)-1207.6 k]/mol So (CaCO3) 91.7 J/mol K AHof (CaO)-35.09 kJ/mol S° (CaO) 38.2 J/mol K AHor (CO2)-393.51 kJ/mol So (CO2)213.74 J/mol K
At what temperature is the following reaction feasible: CaCO3 -> CaO + CO2? Enthalpy data: CaCO3: -1207 kJ/mol CaO: -635 kJ/mol CO2: -394 kJ/mol Entropy data: CaCO3: +93 J/K mol CaO: +40 J/K mol CO2:+214 J/K mol
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for each of the following reactions. (a) CH4(g) + H2O(g) equilibrium reaction arrow CO(g) + 3 H2(g); ?H° = +205.9 kJ, ?S° = +214.7 J/K ?G° 141.9 Correct: Your answer is correct. kJ K (b) CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g); ?H° = +179.2 kJ, ?S° = +160.2 J/K ?G° 131.5 Correct: Your answer is correct. kJ K
Calculate AH for the following reaction, CaO(s) + CO2(g) CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) + 2 Cao(s) AH = -1270.2 kJ C(s) + O2(g) CO2(g) AH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) AH = -2413.8 kJ 0-750.1 kJ O +350.2 kJ 0 -178.3 kJ O +2870.6 kJ
e. -1135 Given the following reactions: CaCO3 (s)-> Cao (s) + CO2 (g) C (s, graphite) + O2 (g)-> Co2 (g) AH-393.5 kJ the enthalpy of the reaction CaCO3 (s) -> CaO (s) + C (s, graphite) + O2 (g) ΔH = 178.1 kJ is kJ Select one: 4 a. 7.01 x 10 b. 571.6 ) c. 215.4 d. -215.4 ie. -571.6 Check Given the data in the table below, AH for the reaction
Part A Calculate AHxn for the following reaction: Cao(s) + CO2(g) +CaCO3(s) Use the following reactions and given AH values: Ca(s) + CO2(g) + O2(g) +CaCO3(s), AH =-812.8 kJ 2Ca(s) + O2(g)+2CaO(s), AH = -1269.8 kJ Express your answer using four significant figures. V AE ? AH, = Submit Request Answer
9. Consider the following reaction: inputted, <GO CaO(s) + CO2(g) - CaCO3(s); AG° = -130.9 kJ at 298 K At what partial pressure of CO2(g) will the reaction no longer be spontaneous at 298 K? (R- 0.0821 L.atm/(K.mol) = 8.31 J/(K.mol)) a. 1.59 x 108 atm b. 1.00 atm c. 6.28 x 10 atm d. 8.77 x 1022 atm e. 1.14 x 10-23 atm
What is K for the following reaction? CaCO3 (s) >>CO2(s) + CaO (s) Delta H=117.8kj/mol Delta S= 160.5 J/kmol Delta G=130.2jk/mol
The decomposition of calcium carbonate is given by the equation, CaCO3(s) →CaO(s) + CO2(g). Determine if the reaction is spontaneous at room temperature, given the following thermodynamics parameters: Δ? = 178 kJ/mol Δ? = 163 J/Kmol
Please don't forgot to calculate the temperature at which the reaction switches . 1. Given the following information, calculate the standard Gibbs free energy of the reaction at 1455 K. State if the reaction is spontaneous or nonspontaneous followed by the temperature at which the reaction switches spontaneity if applicable CaCO3(s) → CaO(s) + CO2(g) Given: Δ"H = 179.2 kJ , Δ"S = 160.2 J/K