Question

11.ExponentialDistribution 1: Problem 4 Previous Problem Problem List Next Problem (1 point) Suppose that the time (in hours)
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Answer #1

Cumulative distribution function

F_X(x)=1-e^-\lambda x

=F_X(x)=1-e^-^0^.^6 ^x

a.)

P(X <4)- Fx(4)

- 0.6 4 * 1-e

0,9093

b.)

P(X\geq 10/X>9)=P(X\geq 9+1/X>9)

P(X > 10/X > 9) PX 1)

P(X > 10/X > 9)-1-P(X < 1)

1 - [1- e-0.6-1

=e^-^0^.^6^*^1

=0.5488

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