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4:54 Previous Problem Problem List Next Problem (1 point) A survey of 1330 people who took trips revealed that 127 of them in
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Answer #1

\widehat p = 0.0955

The test statistic z = (\widehat p - P)/sqrt(P * (1 - P)/n) = ​​​​​​(0.0955 - 0.11)/sqrt(0.11 * 0.89/1330) = -1.69

At alpha = 0.01, the critical value is z0.01 = -2.33

Since the test statistic value is not less than the critical value (-1.69 > -2.33), so we should not reject the null hypothesis.

Option - A) There is not sufficient evidence to support the claim that less than 11% of trips include a theme park visit.

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